10 0 obj H�L�MO�0���>n����~�#qE"�]��v���"�>IZr"G���~S�B�.����˛�! /Rotate 0 endstream endobj 70 0 obj<> endobj 71 0 obj<> endobj 72 0 obj<>/Font<>/ProcSet[/PDF/Text]/ExtGState<>>> endobj 73 0 obj[/ICCBased 78 0 R] endobj 74 0 obj<> endobj 75 0 obj<>stream /Contents 33 0 R <<3C979C6C9C9EE845BD96F93B4D157B17>]>>
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/MediaBox [0 0 612 792] Simulations let us do this for any forces and any initial conditions, even when no explicit formula for the motion exists. 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 /Resources << endobj /Resources << In a projectile motion, the only acceleration acting is in the vertical direction which is acceleration due to gravity (g). /Title (Microsoft Word - Projectile Motion Short.doc) /Flags 32 /Resources << /Font 29 0 R Horizontal distance and displacement can be calculated from the given formula as in the /CreationDate (D:20120820134506) /AP << /MediaBox [0 0 612 792] 13 0 obj ��`1(K�8*i�e���� /ExtGState 22 0 R /Subtype /Type1 Ideally what mathematical curve is the trajectory? endobj HONORS PHYSICS Page 6 . >> HONORS PHYSICS Page 4 . /RC (, Projectile Motion - Version 7.0 - University of Michigan-Dearborn, Microsoft Word - Projectile Motion Short.doc.
0000000955 00000 n /Rotate 0 /F0 6 0 R For now, we will assume that the air, or any other fluid through which the object is moving, does not have any effect on the motion. /Rotate 0 << /Parent 5 0 R 0000049084 00000 n Projectile Motion. '-A�� ��}� �V��)g�B�0�i�W��8#�8wթ��8_�٥ʨQ����Q�j@�&�A)/��g�>'K�� �t�;\�� ӥ$պF�ZUn����(4T�%)뫔�0C&�����Z��i���8��bx��E���B�;�����P���ӓ̹�A�om?�W= 0000038448 00000 n motion, and our goal will be to predict the motion of one or more objects subject to various forces. /Parent 5 0 R /ProcSet [/PDF /Text] /Resources << /ExtGState 46 0 R /ExtGState 25 0 R << PrimoPDF %PDF-1.4 %���� 79 0 obj<>stream N'��)�].�u�J�r� /Contents 45 0 R /ProcSet [/PDF /Text] /Contents 24 0 R /LastChar 255 In this project you’ll simulate the motion of a projectile… /Rotate 0 /Font 47 0 R /Rotate 0
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If you are on a personal connection, like at home, you can run an anti-virus scan on your device to make sure it is not infected with malware. 0000036376 00000 n /BaseFont /CourierNew << /Descent -300 0000040557 00000 n /Length 3198 %���� /Rotate 0 /Type /Page ��w�G� xR^���[�oƜch�g�`>b���$���*~� �:����E���b��~���,m,�-��ݖ,�Y��¬�*�6X�[ݱF�=�3�뭷Y��~dó ���t���i�z�f�6�~`{�v���.�Ng����#{�}�}��������j������c1X6���fm���;'_9 �r�:�8�q�:��˜�O:ϸ8������u��Jq���nv=���M����m����R 4 � 0000000016 00000 n /W 0 >> /Rotate 0 n�3ܣ�k�Gݯz=��[=��=�B�0FX'�+������t���G�,�}���/���Hh8�m�W�2p[����AiA��N�#8$X�?�A�KHI�{!7�. %PDF-1.3 /Contents 30 0 R It is the displacement in the x direction of an object whose displacement in the y direction is zero. 3 Equations of motion: no air resistance We first consider the situation of a projectile launched from a tower of height h onto some impact function , ignoring the e↵ect of air resistance. Projectile motion: f(t) 000 2 000 0 1 2 xxx x yyy y avv xxvt a g v v gt y y v t gt == =+ =− = − = + − initial conditions 00 0 00 0 cos sin x y vv vv θ θ = = v 0 – full initial velocity θ 0 – initial angle �ꇆ��n���Q�t�}MA�0�al������S�x ��k�&�^���>�0|>_�'��,�G! endobj 3 0 obj 5 Projectile Motion >> /ProcSet [/PDF /Text] Analysis, cont ! endobj 8. endobj endobj Projectile Motion Formula Sheet You can find the proofs of these results in our tutorial videos Vertical Motion Acceleration: ̈=− (where g is gravitational pull) Velocity: ̇=−+sin Displacement: = − 2 2 +sin Horizontal Motion t. If we have initial velocity then, our equation becomes; V=Vit+gt where acceleration is -9,8m/s² Distance is calculated considering the initial velocity of the object by the formula; We put “-“sign because direction of g is downward. 0000049934 00000 n endobj /ExtGState 49 0 R endobj
600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 �,�U����`h�b��pdd�U� 0000052291 00000 n
/Type /Font /Creator (PrimoPDF http://www.primopdf.com) 0000050676 00000 n 0000001704 00000 n 0000001385 00000 n Microsoft Word - Projectile Motion Short.doc /Type /Page /Type /Pages /Resources << t. If we have initial velocity then, our equation becomes; V=Vit+gt where acceleration is -9,8m/s² Distance is calculated considering the initial velocity of the object by the formula; We put “-“sign because direction of g is downward. /Type /Page >>
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Make sure you understand The Projectile Motion Equations. endobj /Resources << U��fy�|���h�%S��JBך �7_�,�e����Rm���HR/�"��� 'wtt400 >> ��A|��� Projectile motion problems: Solutions Thursday, October 31, 2013 9:56 AM HONORS PHYSICS Page 1 . /BaseFont /Helvetica << 0000050654 00000 n >>
/Font 53 0 R 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 The path that the object follows is called its trajectory. 0000001165 00000 n %PDF-1.2 %âãÏÓ When the motion is purely vertical, the state of the projectile is de ned by its position, y, and its velocity, v … Describe two examples of projectile motion which you have observed or experienced outside of the physics lab. 0000000516 00000 n /Resources << 10. >> /ExtGState 31 0 R >> /Fields []
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H���yTSw�oɞ����c [���5la�QIBH�ADED���2�mtFOE�.�c��}���0��8��8G�Ng�����9�w���߽��� �'����0 �֠�J��b� The problems include finding the time of flight and range of a projectile, as well as finding the velocity and position at a certain time during the motion. << << For a projectile motion displacement can be calculated from the point of projection along the direction of projection. /ProcSet [/PDF /Text] /FontBBox [-122 -680 623 1021] endobj
Some examples of projectile motion are the motion of a ball after being hit/thrown, the motion of a bullet after being fired and the motion of a person jumping off a diving board. startxref >> What, if any, is the significance of the other sign? 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 0000037104 00000 n /Parent 5 0 R Velocity has two components v c o s θ in horizontal and v s i n θ in vertical direction ,in which horizontal component of velocity remains constant because of absence of force. /Parent 5 0 R /Font 44 0 R 20 0 obj /Rotate 0
Projectile Motion Solved Example. /Resources << /Resources << /MediaBox [0 0 612 792] 69 0 obj <> endobj 11 0 obj /Font 38 0 R endobj At the same time a similar bullet is dropped from the 2y�.-;!���K�Z� ���^�i�"L��0���-�� @8(��r�;q��7�L��y��&�Q��q�4�j���|�9�� /FontFamily (CourierNew) /Annots [20 0 R] %%EOF 7 0 obj
If you are at an office or shared network, you can ask the network administrator to run a scan across the network looking for misconfigured or infected devices. 16 0 obj /MediaBox [0 0 612 792] In the range equation, Eq. 0 600 600 600 600 600 600 600 600 600 600 600 600 0 600 600
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endobj /FontWeight 400 The formula of projectile motion is used to calculate the velocity, distance, and time observed in the projectile motion of the object. 0000001643 00000 n
0 /Count 11 endstream /Widths [600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 Projectile motion only occurs when there is one force applied at the beginning on the trajectory, after which the only interference is from gravity. 0000002027 00000 n 0000001309 00000 n >> 0000054707 00000 n /ProcSet [/PDF /Text]
Problem 1: Jhonson is standing on the top of the building and John is standing down. /Resources << /DS (font-family:Courier New;font-size:12pt;font-style:normal;text-decoration:none;color:#000000;) 15 0 obj
/Contents (Projectile Motion - Version 7.0 - University of Michigan-Dearborn) >> V fy = V 0y + at, therefore, since the final velocity V fy = 0 2. t = V 0y /a, where a = 9.8 m/s >> /Font << PrimoPDF http://www.primopdf.com /FirstChar 32 trailer Projectile Motion Formula _ Formula for Projectile Motion _ Formulas@TutorVista.pdf - Free download as PDF File (.pdf), Text File (.txt) or read online for free. 600 0 600 600 600 600 600 600 600 600 600 600 600 0 600 0 /N 54 0 R /MediaBox [0 0 612 792]
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/Type /Catalog "F$H:R��!z��F�Qd?r9�\A&�G���rQ��h������E��]�a�4z�Bg�����E#H �*B=��0H�I��p�p�0MxJ$�D1��D, V���ĭ����KĻ�Y�dE�"E��I2���E�B�G��t�4MzN�����r!YK� ���?%_&�#���(��0J:EAi��Q�(�()ӔWT6U@���P+���!�~��m���D�e�Դ�!��h�Ӧh/��']B/����ҏӿ�?a0n�hF!��X���8����܌k�c&5S�����6�l��Ia�2c�K�M�A�!�E�#��ƒ�d�V��(�k��e���l ����}�}�C�q�9 9 0 obj >> endobj /MediaBox [0 0 612 792] /Rotate 0 A bullet is fired horizontally from a gun. HONORS PHYSICS Page 5 . We find the velocity of the free falling object by the equation V=g. /Contents 21 0 R Once you know the initial velocity ( v ), launch angle ( α ), and initial height ( h ), use the calculator. 0000002049 00000 n application/pdf
0000054914 00000 n Analyze the vertical motion using constant acceleration techniques ! Enhance your knowledge by visualising projectile motion in possibly the most interesting way. Your IP: 198.167.139.37 /IT /FreeTextTypewriter Finalize! << /DA (0 0 0 rg /F1 12 Tf) 0000040352 00000 n It is derived using the kinematics equations: a x = 0 v x = v 0x x = v 0xt a y = g v y = v 0y gt y = v 0yt 1 2 gt2 where v 0x = v 0 cos v 0y = v 0 sin Suppose a projectile is thrown from the ground level, then the range is the distance between the launch point and the landing point, where the projectile …